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5/2y^2=90
We move all terms to the left:
5/2y^2-(90)=0
Domain of the equation: 2y^2!=0We multiply all the terms by the denominator
y^2!=0/2
y^2!=√0
y!=0
y∈R
-90*2y^2+5=0
Wy multiply elements
-180y^2+5=0
a = -180; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-180)·5
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-180}=\frac{-60}{-360} =1/6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-180}=\frac{60}{-360} =-1/6 $
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